8th Grade Mathematics
End-of-Year Assessment
7th Grade EOG Mathematics Test with Answer Key 202...
6th Grade EOG Mathematics Test with Answer Key 202...
5th Grade Mathematics EOG Test with Answer Key 202...
4th Grade Mathematics End-of-Year Assessment: Par...
Parent Preparation Guide & Complete Examination
|
Aligned To Texas TEKS Mathematics — Grade 8 |
Frameworks Used Bloom's Taxonomy Hess's Cognitive Rigor Matrix |
|
FOR PARENTS: What Is This Document? This
guide contains a complete, rigorous 8th Grade mathematics examination aligned
to the Texas Essential Knowledge and Skills (TEKS). It is designed to help
parents understand what their child is expected to know by the end of 8th
Grade and to prepare them for STAAR. Each question includes the specific TEKS
standard, Bloom's Taxonomy level, Depth of Knowledge (DOK) level, a
parent-friendly explanation of what the question measures, at-home support
activities, and common mistakes to watch for. |
|
PART 1:
NUMBER & EXPONENTS |
Student Name:
___________________________ Date:
_______________ Grade: 8
|
Directions:
Read each question carefully. Show all your work. For multiple-choice
questions, circle the letter of the best answer. For open-response questions,
write your answer and explanation in the space provided. |
|
Question 1 Bloom's: Apply | DOK: 2
| TEKS: 8.2A |
|
Between which two consecutive
integers does √47 lie? Without a calculator, explain your reasoning. Then
determine whether √47 is rational or irrational. |
|
A) 6 and 7 B) 7 and 8 C) 5 and 6 D) 8 and 9 |
|
|
|
Question 2 Bloom's: Apply | DOK: 2
| TEKS: 8.2B |
|
Write 0.000034 in scientific
notation. Then write 2.15 × 10⁶ in standard form. Which number is larger? |
|
Answer:
_______________________________________________ |
|
Question 3 Bloom's: Analyze | DOK: 3
| TEKS: 8.2D |
|
Explain why 2⁻³ is NOT a
negative number. What is its value? Now prove that (2³)(2⁻³) = 1 using the
laws of exponents. What does this tell us about negative exponents? |
|
Answer:
_______________________________________________ |
|
PART 2:
PROPORTIONALITY & LINEAR FUNCTIONS |
|
Question 4 Bloom's: Apply | DOK: 2
| TEKS: 8.4A |
|
A line passes through the
points (2, 5) and (6, 13). A)
Calculate the slope. B) Write the equation in slope-intercept form (y = mx +
b). C) What is the y-intercept and what does it mean in context? |
|
Answer:
_______________________________________________ |
|
Question 5 Bloom's: Analyze | DOK: 3
| TEKS: 8.4C |
|
Two cell phone plans: Plan A: y = 0.10x + 25 (x = minutes, y =
monthly cost) Plan B: y = 0.05x +
40 A) What does the slope mean in each
plan? The y-intercept? B) For what number of minutes is Plan A cheaper? C)
Graph both lines (describe the graph — where do they intersect?) |
|
Answer:
_______________________________________________ |
|
PART 3:
EXPRESSIONS, EQUATIONS & SYSTEMS |
|
Question 6 Bloom's: Apply | DOK: 2
| TEKS: 8.9A |
|
Solve the system of equations
by substitution: y = 3x - 4 2x + y = 11 Check your solution by substituting back
into both original equations. |
|
Answer:
_______________________________________________ |
|
Question 7 Bloom's: Analyze | DOK: 3
| TEKS: 8.9A |
|
A system of equations can have
one solution, no solution, or infinitely many solutions. For each case below, determine the number
of solutions WITHOUT solving. Explain how you know: A) y = 2x + 5 and y = 2x - 3 B) y = 4x + 1 and 2y = 8x + 2 C) y = -x + 6 and y = 2x - 3 |
|
Answer:
_______________________________________________ |
|
PART 4:
GEOMETRY & MEASUREMENT |
|
Question 8 Bloom's: Apply | DOK: 2
| TEKS: 8.7A |
|
A right triangle has legs of 9
cm and 12 cm. Use the Pythagorean Theorem to find the hypotenuse. Then
verify: could the sides 5, 12, 13 form a right triangle? Show your work. |
|
A) 15 cm; Yes B) 21 cm; Yes C) 15 cm; No D) √153; Yes |
|
|
|
Question 9 Bloom's: Analyze | DOK: 3
| TEKS: 8.7C |
|
A ladder 10 feet long leans
against a wall. The base of the ladder is 6 feet from the wall. A) How high up the wall does the ladder
reach? B) If the base is moved to 8 feet from the wall (for safety), how high
does it now reach? C) Which placement is safer? Which reaches higher? Is
there a trade-off? |
|
Answer:
_______________________________________________ |
|
PART 5:
DATA, STATISTICS & PROBABILITY |
|
Question 10 Bloom's: Apply | DOK: 2
| TEKS: 8.11A |
|
The scatter plot data shows
study time (x, in hours) and test scores (y):
(1,65), (2,70), (3,78),
(4,80), (5,88), (6,92) A) Describe the
association (positive/negative, strong/weak, linear/nonlinear). B) Estimate
the line of best fit equation. C) Predict the score for 7 hours of study. |
|
Answer:
_______________________________________________ |
|
Question 11 Bloom's: Evaluate
| DOK: 3 |
TEKS: 8.11B |
|
An advertisement claims:
'Students who use our tutoring service score 95% higher on tests!' The data
shows: average score before = 60, average score after = 63. A) Calculate the actual percent increase.
B) Is the advertisement's claim accurate? What is misleading about it? C) Why
might correlation in test score data not mean tutoring CAUSED the
improvement? |
|
Answer:
_______________________________________________ |
|
PART 6:
EXTENDED PROBLEM SOLVING |
|
Question 12 Bloom's: Analyze | DOK: 3
| TEKS: 8.4/8.7/8.9 |
|
A park design problem: A rectangular park is 80 m × 60 m. A
diagonal walking path crosses the park. A) How long is the diagonal path? B)
A fence will cost $15/m along the perimeter and $22/m along the diagonal.
What is the total fencing cost? C) The city can only spend $8,500 on fencing.
Can they build the complete fence? By how much are they over or under budget? |
|
Answer:
_______________________________________________ |
|
Question 13 Bloom's: Create | DOK: 4
| TEKS: All Domains |
|
CAPSTONE PROJECT: Mathematical
Modeling Challenge You are a city
planner. Design a plan for a small community park that includes: (1) A rectangular main area with
dimensions you choose (2) A circular
fountain in the center (you choose the radius) (3) A diagonal walking path (4) A budget analysis (you set realistic
prices per unit) (5) A linear
equation modeling visitor count vs. days open (6) A probability analysis: if 3 visitors
are chosen randomly for a survey from a group of 5 men and 4 women, what is
P(all 3 are women)? All parts must be
calculated, justified, and presented as a coherent plan. |
|
Answer:
_______________________________________________ |
COMPLETE ANSWER KEY
For
Parent and Educator Use
|
Q# |
Answer |
Explanation |
TEKS |
|
1 |
A) 6 and 7;
√47 is irrational. |
6²=36, 7²=49.
Since 36<47<49, then 6<√47<7. 47 is not a perfect square, so √47
is irrational (non-terminating, non-repeating decimal). |
8.2A |
|
2 |
0.000034 =
3.4 × 10⁻⁵. 2.15 × 10⁶ = 2,150,000. 2.15 × 10⁶ is vastly larger. |
For 0.000034:
move decimal 5 places right → 3.4 × 10⁻⁵. For 2.15×10⁶: move decimal 6 places
right → 2,150,000. |
8.2B |
|
3 |
2⁻³ = 1/8
(positive). (2³)(2⁻³) = 2^(3+(-3)) = 2⁰ = 1. Negative exponents mean
reciprocals: a⁻ⁿ = 1/aⁿ. |
2⁻³ = 1/2³ =
1/8 ≈ 0.125. Not negative — it's a positive fraction. Product rule: 2³ × 2⁻³
= 2⁰ = 1, confirming that 2³ and 2⁻³ are reciprocals. |
8.2D |
|
4 |
A) m = 2.
B) y = 2x + 1. C) y-intercept = 1 — when x=0, y=1 (the starting value). |
m =
(13-5)/(6-2) = 8/4 = 2. Using (2,5): 5 = 2(2)+b → b=1. Equation: y=2x+1. |
8.4A |
|
5 |
A)
Slope=cost per minute; y-intercept=base fee. B) Plan A cheaper when x<300.
C) Lines intersect at (300, 55). |
Set equal:
0.10x+25=0.05x+40 → 0.05x=15 → x=300. At 300 min both cost $55. Below 300, A
is cheaper. Above, B is cheaper. |
8.4C |
|
6 |
x = 3, y =
5. Check: y=3(3)-4=5 ✓. 2(3)+5=11 ✓. |
Substitute: 2x
+ (3x-4) = 11 → 5x-4=11 → 5x=15 → x=3. y=3(3)-4=5. Solution: (3,5). |
8.9A |
|
7 |
A) No
solution (parallel lines — same slope, different intercepts). B) Infinite
solutions (same line). C) One solution (different slopes → intersect). |
A) Both
slope=2, different intercepts → parallel. B) Divide second by 2: y=4x+1 —
identical to first → same line. C) Slopes -1 and 2 differ → one intersection
point. |
8.9A |
|
8 |
A) 15 cm;
Yes (5²+12²=25+144=169=13²). |
9²+12²=81+144=225=15².
Hyp=15. Check: 5²+12²=169=13². Yes, right triangle. |
8.7A |
|
9 |
A)
√(100-36)=√64=8 ft. B) √(100-64)=√36=6 ft. C) Farther base = safer but lower
reach. Trade-off between safety and height. |
Pythagorean:
6²+h²=10² → h=8. 8²+h²=10² → h=6. As base increases, height decreases. This
illustrates the inverse relationship — a real trade-off in ladder safety. |
8.7C |
|
10 |
A) Strong
positive linear association. B) Approx: y = 5.5x + 59. C) ≈ 97.5. |
The data
increases steadily and nearly linearly. Slope ≈ (92-65)/(6-1) = 27/5 = 5.4.
Using (1,65): 65=5.4(1)+b → b≈59.6. Predict 7 hrs: 5.5(7)+59=97.5. |
8.11A |
|
11 |
A)
(63-60)/60 = 5% increase. B) Claim is false (95% vs. 5%). C) Other factors
(harder study habits, better sleep, teacher change) may have caused
improvement — correlation ≠ causation. |
Actual
increase: 5%. The ad falsely claimed 95%. Also: students who seek tutoring
may also study harder independently. Self-selection bias means the
improvement may not be caused by the tutoring itself. |
8.11B |
|
12 |
A) 100 m.
B) Perimeter: $4,200. Diagonal: $2,200. Total: $6,400. C) Under budget by
$2,100. |
A)
√(80²+60²)=√(6400+3600)=√10000=100m. B) Perimeter: 2(80+60)=280m ×
$15=$4,200. Diagonal: 100×$22=$2,200. Total=$6,400. Under $8,500 by $2,100. |
8.4/8.7/8.9 |
|
13 |
Answers
vary. Full credit: valid geometry calculations, complete budget, linear
equation with interpretation, P(all 3 women) = (4/9)(3/8)(2/7) = 24/504 =
1/21 ≈ 4.76%. |
P(1st
woman)=4/9. P(2nd|1st)=3/8. P(3rd|first two)=2/7. Combined:
4/9×3/8×2/7=24/504=1/21. All geometry and budget should be internally
consistent with student's chosen dimensions. |
All Domains |
PARENT GUIDE
Understanding Every Question: What It Measures & How
to Help
|
Q1:
Estimating Irrational Square Roots TEKS 8.2A |
Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Students
reason about irrational numbers without a calculator — understanding that
most square roots are irrational and developing number sense about their
approximate location on the number line. How to
Help Your Child at Home: Practice
perfect squares (1,4,9,16,25,36,49,64,81,100). Then estimate: 'Between which
two perfect squares does 50 fall? 75? 30?' The pattern of reasoning
(comparison to perfect squares) is the key skill. Watch For
/ Common Mistakes: Students
may compute a decimal approximation on a calculator without engaging the
conceptual reasoning. Require them to FIRST explain using perfect squares,
THEN verify with a calculator. |
|
Q2:
Scientific Notation — Very Small and Very Large Numbers TEKS 8.2B |
Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Scientific
notation is the language of science — used for atomic measurements,
astronomical distances, and everything in between. Students must convert in
both directions and compare magnitudes. How to
Help Your Child at Home: Look up
real measurements: diameter of a human hair (~0.00007 m = 7×10⁻⁵ m), distance
to the sun (~150,000,000 km = 1.5×10⁸ km). Convert back and forth. Connect to
science class! Watch For
/ Common Mistakes: For small
numbers, students often write the exponent as positive (3.4 × 10⁵ instead of
10⁻⁵). The decimal moved RIGHT (toward larger) → NEGATIVE exponent. Think:
making a tiny number requires a negative power of 10. |
|
Q3:
Negative Exponents — Understanding the Pattern TEKS 8.2D |
Bloom's: Analyze | DOK: 3 |
|
What This
Question Measures: DOK 3 —
students must explain, prove, and derive the meaning of negative exponents
from the laws of exponents. This is conceptual understanding of exponents at
its deepest level. How to
Help Your Child at Home: Build a
table: 2⁴=16, 2³=8, 2²=4, 2¹=2, 2⁰=1, 2⁻¹=?, 2⁻²=? Ask: 'Each step we divide
by 2. What comes after 1? After 1/2?' Let the pattern reveal the meaning of
negative exponents. Watch For
/ Common Mistakes: 'Negative
exponent means negative number' is the most persistent misconception. 2⁻³ =
1/8 = 0.125 — positive, less than 1. Use the table approach to let students
discover the pattern rather than just memorizing the rule. |
|
Q4:
Slope-Intercept Form — Writing Linear Equations TEKS 8.4A |
Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Students
find slope, write linear equations, and interpret the y-intercept — core 8th
grade algebra skills that connect to every STEM field and to the modeling of
real-world change over time. How to
Help Your Child at Home: Graph
real data: your child's height at different ages, temperature throughout the
day, distance over time on a walk. Find the slope (rate of change) and
y-intercept (starting value). Make linear equations come alive. Watch For
/ Common Mistakes: Students
often subtract coordinates in the wrong order for slope: (y₁-y₂)/(x₁-x₂)
instead of (y₂-y₁)/(x₂-x₁). Both are correct IF consistent — but mixing
orders is the error. Teach a consistent procedure. |
|
Q5:
Interpreting Linear Equations — Slope and Intercept in Context TEKS 8.4C |
Bloom's: Analyze | DOK: 3 |
|
What This
Question Measures: Students
interpret slope and y-intercept in a real-world context AND find the
intersection of two linear equations — combining graphical, algebraic, and
contextual understanding. How to
Help Your Child at Home: Compare
two actual phone or subscription plans your family uses. Identify fixed cost
and per-unit cost. Write equations. Find when they're equal. Decide which
plan suits your usage. This is exactly how adults make contract decisions. Watch For
/ Common Mistakes: Students
may solve the system algebraically but then fail to interpret the meaning:
'Plan A is cheaper for fewer than 300 minutes.' The mathematical answer
(x=300) must be connected to the real-world decision. |
|
Q6:
Systems of Equations — Substitution Method TEKS 8.9A |
Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Students
solve a 2×2 system of linear equations using substitution — a foundational
algebra skill directly tested on STAAR and required for all high school
mathematics. How to
Help Your Child at Home: Present
as a puzzle: 'Two numbers. The first is 3 times the second minus 4. Together,
double the second plus the first equals 11. Find both numbers.' Algebra as
puzzle-solving makes it engaging. Watch For
/ Common Mistakes: The most
common error: after finding x=3, students substitute into one equation and
stop without verifying the second. Checking both equations is not optional —
it builds mathematical rigor and catches errors. |
|
Q7:
Classifying Systems of Equations — Geometric Reasoning TEKS 8.9A |
Bloom's: Analyze | DOK: 3 |
|
What This
Question Measures: DOK 3 —
students analyze the structure of linear equations to predict the number of
solutions without solving — a sophisticated geometric insight connecting
algebra to the visual behavior of lines. How to
Help Your Child at Home: Graph all
three systems together. Let your child see that parallel lines never meet,
identical lines overlap everywhere, and lines with different slopes always
cross. The visual makes the algebraic reasoning intuitive. Watch For
/ Common Mistakes: Students
may try to solve each system algebraically — which works but misses the
conceptual point. Push them to compare slopes and intercepts FIRST. This is
faster AND demonstrates deeper understanding. |
|
Q8:
Pythagorean Theorem — Application and Verification TEKS 8.7A |
Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Students
apply the Pythagorean Theorem to find a missing side AND verify whether three
given lengths form a right triangle — two distinct but related skills
essential for geometry and trigonometry. How to
Help Your Child at Home: Measure
diagonals of rectangular objects. Verify: if a TV is 16 inches wide and 12
inches tall, the diagonal should be 20 inches. Check it! This makes the
theorem physically real and memorable. Watch For
/ Common Mistakes: Students
often use the formula as a + b = c (adding, not squaring). The squares are
essential: a² + b² = c². Also: the hypotenuse is ALWAYS the longest side — if
students get a hypotenuse shorter than a leg, they've made an error. |
|
Q9:
Pythagorean Theorem — Design Trade-offs in Real Engineering TEKS 8.7C |
Bloom's: Analyze | DOK: 3 |
|
What This
Question Measures: Students
apply the theorem twice and analyze a real trade-off — higher safety means
lower reach. This is engineering reasoning using geometry: understanding that
design decisions involve competing constraints. How to
Help Your Child at Home: Look up
ladder safety guidelines (OSHA recommends a 4:1 ratio — for every 4 feet of
height, base should be 1 foot out). Calculate: at 8 feet high, the safe base
is 2 feet. Does this match our calculation? Watch For
/ Common Mistakes: Students
may correctly find heights but then struggle to articulate the trade-off.
Require a clear sentence: 'Moving the base farther makes the ladder safer but
it reaches less high.' The qualitative conclusion matters as much as the
numbers. |
|
Q10:
Scatter Plots, Association, and Lines of Best Fit TEKS
8.11A | Bloom's: Apply | DOK: 2 |
|
What This
Question Measures: Students
analyze scatter plot patterns, describe the association, estimate a line of
best fit, and make predictions — core data literacy skills that bridge
statistics, algebra, and real-world reasoning. How to
Help Your Child at Home: Collect
your own data over several weeks (study time vs. quiz scores, sleep vs.
performance). Plot it. Draw a line of best fit. Make predictions. Compare
predictions to actual results. This is real scientific method. Watch For
/ Common Mistakes: Students
may draw a line connecting only the first and last points, ignoring the
middle data. The line of best fit should be drawn through the MIDDLE of the
data, with roughly equal numbers of points above and below. |
|
Q11:
Statistical Reasoning — Evaluating Claims, Causation vs. Correlation TEKS
8.11B | Bloom's: Evaluate | DOK: 3 |
|
What This
Question Measures: DOK 3 —
students evaluate a real-world advertising claim using statistics, compute an
accurate percent, identify misleading language, and distinguish correlation
from causation — the most sophisticated statistical thinking in 8th grade. How to
Help Your Child at Home: Collect
real misleading statistics from advertisements or news. Compute what the
numbers actually say. Discuss: 'Could something else explain this? Could the
data be true but presented misleadingly?' This is critical media literacy. Watch For
/ Common Mistakes: Students
may accept '95% higher' without computing the actual change. The habit of
VERIFYING statistical claims — not accepting them at face value — is the most
important life skill this course teaches. |
|
Q12:
Pythagorean Theorem + Perimeter + Budget — Engineering Design TEKS
8.4/8.7/8.9 | Bloom's: Analyze | DOK: 3 |
|
What This
Question Measures: Students
integrate the Pythagorean Theorem, perimeter, and financial reasoning in a
multi-part engineering design problem — the kind of integrated, realistic
problem that defines real-world mathematical modeling. How to
Help Your Child at Home: Design
your ideal park or room on graph paper. Add a diagonal path or feature.
Calculate all dimensions using the Pythagorean Theorem. Research realistic
costs for materials. Determine if your design fits your budget. Watch For
/ Common Mistakes: Students
may forget to include BOTH the perimeter fence AND the diagonal fence, or may
compute the diagonal as 80+60=140 instead of √(80²+60²)=100. Emphasize: the
diagonal of a rectangle is NOT the sum of the two sides. |
|
Q13: City
Park Design — Full Mathematical Modeling Capstone TEKS All
Domains | Bloom's: Create | DOK: 4 |
|
What This
Question Measures: Bloom's
CREATE at DOK 4 — the ultimate 8th grade mathematical challenge. Students
design a real-world system using geometry, algebra, probability, and
financial reasoning. This is authentic mathematical modeling: the work real
engineers, architects, and city planners do. How to
Help Your Child at Home: This can
be a family project! Design your dream community park together. Research real
costs for fencing, fountains, and paving. Calculate everything. Present it as
a real proposal — to a 'city council' of family members. Make mathematics a
creative, collaborative act. Watch For
/ Common Mistakes: Internal
consistency is key: if the student chooses a 100m × 80m park, all subsequent
calculations must use those dimensions. A beautiful plan with correct math
earns full credit. Make sure the probability in Part 6 uses the
without-replacement method (conditional probability). |
Scoring Guide & Next Steps
|
Score |
Performance Level |
Recommended
Action |
|
27–30 |
Masters Grade Level |
Excellent!
Focus on enrichment and extension. Explore real-world applications and the
next grade's preview topics. |
|
22–26 |
Meets Grade Level |
Strong!
Review missed questions by domain. Use the Parent Guide tips for weak areas. |
|
16–21 |
Approaches Grade Level |
Spend 15
minutes daily on the domains where most questions were missed. Use hands-on
activities from the guide. |
|
0–15 |
Developing Foundational Skills |
Schedule time
with the teacher. Focus on the first two TEKS domains — they are the
foundation for everything else. |
This guide was developed using Texas TEKS Mathematics
standards for Grade 8, Bloom's Revised Taxonomy, and Hess's Cognitive Rigor
Matrix. All questions are original and written to mirror STAAR-aligned rigor.
Designed to bridge classroom learning and home support.
No comments:
Post a Comment
Thank you!